Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me answer: A machine gun fires a bullet of mass 40g with a velocity 1200 ms-1 The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ?

A machine gun fires a bullet of mass 40g with a velocity 1200 ms-1 The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ?

  • Option 1)

    one

  • Option 2)

    four

  • Option 3)

    two

  • Option 4)

    three

 

Answers (1)

best_answer

As we learnt in

Newton's 2nd Law -

F\propto \frac{dp}{dt}

F=\tfrac{kdp}{dt} 

F=\tfrac{d\left (mv \right )}{dt} 

F=\tfrac{m\left (dv \right )}{dt}

\frac{dv}{dt}=a

Therefore  F=ma

- wherein

K=1 in C.G.S & S.I

 

 

 

Suppose he can fire n bullets per second

Force = Change in momentum per second

144= n\times \left ( \frac{40}{1000} \right )\times \left ( 1200 \right )

or\: \:\: \: n= \frac{144\times 1000}{40\times 1200}

or\: \:\: \: n= 3

Correct option is 4.


Option 1)

one

This is an incorrect option.

Option 2)

four

This is an incorrect option.

Option 3)

two

This is an incorrect option.

Option 4)

three

This is the correct option.

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Advanced 2024: Chemical engineering cut-offs at IITs; know opening, closing ranks
anam-khan

IIT JEE Mains Result 2024 Session 2: How is overall merit list prepared?
anam-khan

JEE Mains Session 2 result 2024 soon; List of top NITs in India

Latest Question