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Answers (1)

$\frac{dx}{dn}= L\left \{ \frac{\left ( n+2 \right )1-\left ( n+1 \right )}{\left ( n+2 \right )^{2}} \right \}= \frac{L}{\left ( n+2 \right )^{2}}$

If the rod has the same density as  at x = 0  ie ;  n = 0

therefore uniform, the centre of mass would have been at L/2 .  As the density increases with length, the centre of mass shifts towards the right

Therefore it can only be  (2)

Option 1)

It is an incorrect option.

Option 2)

It is the correct option.

Option 3)

It is an incorrect option.

Option 4)

It is an incorrect option.

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