An ionic compound has a unit cell consisting of A  ions at the corners of a cube and B ions on the centres of the faces of the cube. The empirical formula for this compound would be

  • Option 1)

    AB

  • Option 2)

    A_{2}B

  • Option 3)

    AB_{3}

  • Option 4)

    A_{3}B

 

Answers (2)

As we learnt in

No. of atoms(z) for face centered unit cell -

Lattice points: at corners and face centers of unit cell.

For face centered cubic (FCC), z=4.

- wherein

 

 

No. of atoms(z) for simple cubic unit cell -

Lattice points: at corners

For simple cubic (SC), z=1

- wherein

 

 

 

 

Number of A  ions per unit cell = \frac{1}{8}\times 8= 1

Number of B ions per unit cell = \frac{1}{2}\times6= 3

Empirical\: formula\: = AB_{3}

Correct option is 3.

 


Option 1)

AB

This is an incorrect option.

Option 2)

A_{2}B

This is an incorrect option.

Option 3)

AB_{3}

This is the correct option.

Option 4)

A_{3}B

This is an incorrect option.

N neha

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