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Both the nucleus and the atom of some element are in their respective first excited
states. They get de-excited by emitting photons of wavelengths \lambda _{N}, \lambda _{A}, 
respectively. The ratio \lambda _{N}/ \lambda _{A}is closest to :

  • Option 1)

    10^{-6}

  • Option 2)

    10

  • Option 3)

    10^{-10}

  • Option 4)

    10^{-1}

 

Answers (2)

best_answer

As we have learned

γ decay -

\gamma ray emitted when nucleus undergoes radio active decay left it in excited state 

- wherein

After emission of \alpha ,\beta  particle the product nucleus formed in excited state

 

 

nucleus emit radition of order of 0.1A^{0}

atom emits radiation of order of 10^{5}A^{0}

ratio \frac{\lambda _{N}}{\lambda _{a}}= \frac{0.1}{10^{5}}=10^{-6}


Option 1)

10^{-6}

This is correct

Option 2)

10

This is incorrect

Option 3)

10^{-10}

This is incorrect

Option 4)

10^{-1}

This is incorrect

Posted by

Avinash

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