The term independent of x in the expansion of 

(\frac{1}{60}-\frac{x^{8}}{81})\cdot (2x^{3}-\frac{3}{x^{2}})^{6} is equal to :

  • Option 1)

    -72

  • Option 2)

    36

  • Option 3)

    -36

  • Option 4)

    -108

 

Answers (1)

The term independent of x in the expansion of 

(\frac{1}{60}-\frac{x^{8}}{81})\cdot (2x^{3}-\frac{3}{x^{2}})^{6}

=> \frac{1}{60}\times2^{3}\times(-3)^{3}\times C_3^{6}+(\frac{-1}{81})(2)(-3)^{5}\times C_1^{6}

=>-72+36=-36 


Option 1)

-72

Option 2)

36

Option 3)

-36

Option 4)

-108

Most Viewed Questions

Preparation Products

Knockout JEE Main (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Knockout JEE Main (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-
Buy Now
Test Series JEE Main 2024

Chapter/Subject/Full Mock Tests for JEE Main, Personalized Performance Report, Weakness Sheet, Complete Answer Key,.

₹ 7999/- ₹ 4999/-
Buy Now
Knockout JEE Main (One Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 7999/- ₹ 4999/-
Buy Now
Knockout JEE Main (Twelve Months Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 19999/- ₹ 14499/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions