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Help me answer: - Current Electricity - JEE Main

If in the circuit, power dissipation is 150 W, then R is

  • Option 1)

    2\Omega

  • Option 2)

    \; \; 6\Omega \;

  • Option 3)

    \; 5\Omega \;

  • Option 4)

    \; 4\Omega

 
Answers (1)
119 Views

As we learnt in

if R=r -

P_{max}=\frac{E^{2}}{4r}

- wherein

Power delivered will be maximum

 

 and

 

Parallel Grouping -

Potential - Same

Current - Different

- wherein

 

 R_{eq}=\frac{2R}{R+2}

\Rightarrow P=\frac{V^{2}}{R_{eq}}

150=\frac{15^{2}}{R_{eq}}

=R_{eq} = \frac{3}{2}

=\frac{2R}{R+2}

=\frac{3}{2}

R=6\Omega

 

 


Option 1)

2\Omega

This option is incorrect.

Option 2)

\; \; 6\Omega \;

This option is correct.

Option 3)

\; 5\Omega \;

This option is incorrect.

Option 4)

\; 4\Omega

This option is incorrect.

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