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 A series LR circuit is connected to a voltage source with V(t) = V0  sint.  After very large time, current  I(t)  behaves as

\left ( t_{0}\gg \frac{L}{R} \right ) :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)


Answers (1)



As we learnt in

Equation of V -

V= V_{0}\sin \omega t=V_{0}\sin 2\: \pi\: \nu\: t

V= V_{0}\sin \frac{2\pi }{T}t

- wherein

\omega= Angular frequency

\nu = Frequency

T =  time period



V(t) = V_{o} sinwt (t_{o} \gg \frac{L}{R})

I = I_{o} cos (wt + \phi )

Option 1)

This option is incorrect.

Option 2)

This option is correct.

Option 3)

This option is incorrect.

Option 4)

This option is incorrect.

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