A series LR circuit is connected to a voltage source with V(t) = V0  sint.  After very large time, current  I(t)  behaves as

\left ( t_{0}\gg \frac{L}{R} \right ) :
 

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 

Answers (1)

 

As we learnt in

Equation of V -

V= V_{0}\sin \omega t=V_{0}\sin 2\: \pi\: \nu\: t

V= V_{0}\sin \frac{2\pi }{T}t

- wherein

\omega= Angular frequency

\nu = Frequency

T =  time period

 

 

V(t) = V_{o} sinwt (t_{o} \gg \frac{L}{R})

I = I_{o} cos (wt + \phi )


Option 1)

This option is incorrect.

Option 2)

This option is correct.

Option 3)

This option is incorrect.

Option 4)

This option is incorrect.

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Knockout JEE Main January 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions