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# Help me answer: - Laws of motion - JEE Main

A Particle of mass 0.3 kg  is subjected to a force with   What will be its initial acceleration if it is released from a point  20 cm away from the origin ?

• Option 1)

• Option 2)

• Option 3)

• Option 4)

Answers (1)
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As we learnt in

Spring force -

$F= -Kx$

- wherein

$K=\left | \frac{F}{x} \right |= \frac{N}{m}$

$F=\: -\: k\: x$

$or \: \: \: F= -15\times \left ( \frac{20}{100} \right )= -3 N$

Initial acceleration is over come by retarding force.

$or \: \: \: m\times \left ( acceleration\: a \right )= 3$

$or \: \: \: a= \frac{3}{m}= \frac{3}{0.3}= 10ms^{-2}$

Correct option is 2.

Option 1)

This is an incorrect option.

Option 2)

This is the correct option.

Option 3)

This is an incorrect option.

Option 4)

This is an incorrect option.

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