# Two simple harmonic motions are represented by the equations The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is Option 1) Option 2) Option 3) Option 4)

As we learnt in

Phase -

The quantity is called the phase . It determines the status of the particle in simple harmonic motion.

- wherein

e.g.

phase

$v_{1}= \frac{d}{dt}\left ( y_{1} \right )= \left ( 0.1\times 100\pi \right )\cos \left ( 100\pi t+\frac{\pi }{3} \right )$

$v_{2}= \frac{d}{dt}\left ( y_{2} \right )=\left ( -0.1\times \pi \right )\sin \pi t$

$= \left ( 0.1\times \pi \right )\cos \left ( \pi t+\frac{\pi }{2} \right )$

$\therefore \: \: \: \Delta \phi = \frac{\pi }{3}-\frac{\pi }{2}= -\frac{\pi }{6}$

Correct option is 3.

Option 1)

This is an incorrect option.

Option 2)

This is an incorrect option.

Option 3)

This is the correct option.

Option 4)

This is an incorrect option.

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