The correct statement among the following is : 

  • Option 1)

    \left ( SiH_{3} \right )_{3}N is pyramidal and less basic than \left (CH_{3} \right )_{3}N.
     

  • Option 2)

    \left ( SiH_{3} \right )_{3}Nnis planar and less basic than  \left (CH_{3} \right )_{3}N.

  • Option 3)

    \left ( SiH_{3} \right )_{3}N is planar and more basic than \left (CH_{3} \right )_{3}N.

     

  • Option 4)

    \left ( SiH_{3} \right )_{3}N is pyramidal and more basic than \left (CH_{3} \right )_{3}N.

Answers (1)

 

Electronegativity of Nitrogen family -

Gradually decreases down the group. More electronegative than group 14

-

 

 

 

Positive oxidation state of Nitrogen family -

Shows +3 and +5 oxidation states (except N2)

Stability of +3O.S increases down the group due to inert pair effect

- wherein

+3 when only p electron are involved and +5 when all valence five (s and p) electrons are involved

 

 

Negative oxidation state of Nitrogen family -

Exhibits -3 O.S, decreases on moving down the group

-

 

 

 

 

\left ( SiH_{3} \right )_{3}N is planar & less basic than \left ( CH_{3} \right )_{3}N.

Because, lone pair of Nitrogen-atom is in unhybridised p-orbital & it overlaps with d-orbital of si-atom, thus planar in nature. 

\left ( SiH_{3} \right )_{3}N is less basic than \left ( CH_{3} \right )_{3}N as lone pair of electrons on nitrogen-atom is in conjugation with all Si-atoms. 

 


Option 1)

\left ( SiH_{3} \right )_{3}N is pyramidal and less basic than \left (CH_{3} \right )_{3}N.
 

Option 2)

\left ( SiH_{3} \right )_{3}Nnis planar and less basic than  \left (CH_{3} \right )_{3}N.

Option 3)

\left ( SiH_{3} \right )_{3}N is planar and more basic than \left (CH_{3} \right )_{3}N.

 

Option 4)

\left ( SiH_{3} \right )_{3}N is pyramidal and more basic than \left (CH_{3} \right )_{3}N.

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