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Help me answer: The solubility of N2(g) in water exposed to the atmosphere, when the partial pressure is 593 mm is5.3 × 10-4M. Its solubility at 760 mm and at the same temperature is :

The solubility of N2(g) in water exposed to the atmosphere, when the partial pressure is 593 mm is 5.3 × 10-4M. Its solubility at 760 mm and at the same temperature is :

  • Option 1)

    4.1 × 10-4 M

  • Option 2)

    6.8 × 10-4 M

  • Option 3)

    1500 M

  • Option 4)

    2400 M

 
Answers (1)
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As we learned

 

Henry's Law -

It decides the solubility of gases in liquids.

P_{gas}= K_{H}X_{gas}

X_{gas} = mole fraction of gas in liquid.

P_{gas} = Partial pressure of gas over liquid surface.

-

 

 

 

Solution\propto Pressure

\frac{S_{2}}{S_{1}}=\frac{P_{2}}{P_{1}}

S_{2}=5.3\times 10^{-4}\times \frac{760}{593}=6.8\times 10^{-4}M

 


Option 1)

4.1 × 10-4 M

Option 2)

6.8 × 10-4 M

Option 3)

1500 M

Option 4)

2400 M

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