Q&A - Ask Doubts and Get Answers
Q

Help me answer: - Trigonometry - JEE Main-5

What is the solution set of the equation  \csc x > 1 in the interval [0,2 \pi ] ? 

  • Option 1)

    [0, 2\pi ]

  • Option 2)

    [0, 2\pi ]- \left \{ \pi \right \}

  • Option 3)

    [0, 2\pi ]- \left \{ \pi/2 , 3 \pi/2 \right \}

  • Option 4)

    [0, 2\pi ]- \left \{ \pi/2, \pi, 3 \pi /2 \right \}

 
Answers (1)
86 Views

As we have learned

Graph of Trigonometric Ratios -

graph 5

- wherein

This is the graph of y = \csc x

 

 As seen in the graph the graph is always on or above the line x = 1 or on below the linbe x =-1 

Thus  cosec x > 1 will be x \epsilon [0, 2\pi ]- \left \{ \pi/2 , 3\pi/2 \right \} because at x = \pi/2 , 3\pi/2 ; 

cosec x = 1 

 


Option 1)

[0, 2\pi ]

Option 2)

[0, 2\pi ]- \left \{ \pi \right \}

Option 3)

[0, 2\pi ]- \left \{ \pi/2 , 3 \pi/2 \right \}

Option 4)

[0, 2\pi ]- \left \{ \pi/2, \pi, 3 \pi /2 \right \}

Exams
Articles
Questions