Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me answer: - Two-dimensional Coordinate Geometry - BITSAT

If y=2x+k is a diameter to the circle 2(x^{2}+y^{2})+3x+4y-1=0,then\: K\: equals

  • Option 1)

    0

  • Option 2)

    1

  • Option 3)

    +2

  • Option 4)

    +\frac{1}{2}

 

Answers (1)

best_answer

 

General form of a circle -

x^{2}+y^{2}+2gx+2fy+c= 0
 

- wherein

centre = \left ( -g,-f \right )

radius = \sqrt{g^{2}+f^{2}-c}

 

 Centre =\left ( \frac{-3}{4}, -1 \right )

so,

-1=2\times \frac{-3}{4}+K

K=\frac{1}{2}

 

 


Option 1)

0

This is incorrect option

Option 2)

1

This is incorrect option

Option 3)

+2

This is incorrect option

Option 4)

+\frac{1}{2}

This is correct option

Posted by

divya.saini

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT 2025 syllabus out; registration link active at bitsadmission.com
anam-khan

BITSAT 2025 registration link active at bitsadmission.com; exam schedule, eligibility criteria
anam-khan

BITSAT 2025 registration begins today for 10 BE, 6 MSc, BPharm courses; eligibility, fee

Latest Question