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# Help me answer: Two identical parallel plate capacitors are connected in series to a battery of 50V. A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will

Two identical parallel plate capacitors are connected in series to a battery of 50V. A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will now be respectively

• Option 1)

50V, 50V

• Option 2)

40V, 10V

• Option 3)

10V, 40V

• Option 4)

None of these

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As we learnt in

Series Grouping -

$\dpi{100} \frac{1}{C_{eq}}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\cdots$

- wherein

$q=\left ( C_{eq} \right )50 = \frac{4C\times C}{4C+C}.50 = 40C$

$\Rightarrow V_{1} = \frac{40C}{C} = 40 \ V$

$\Rightarrow V_{2} =\frac{40C}{4C} = 10 \ V$

Option 1)

50V, 50V

This option is incorrect

Option 2)

40V, 10V

This option is correct

Option 3)

10V, 40V

This option is incorrect

Option 4)

None of these

This option is incorrect

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