What is the change in surface energy, when a mercury drop of radius R splits up into 1000 droplets of radius r?

  • Option 1)

    8\rho R^{2}T

  • Option 2)

    16 \rho R^{2}T

  • Option 3)

    24 \rho R^{2}T

  • Option 4)

    36 \rho R^{2}T

 

Answers (1)

As we discussed in concept

Surface Energy -

It is defined as the amount of work done in increasing the area of the liquid against surface tension.

-

 

  n\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi R^{3}

nr^{3}=R^{3}

=> R=n^{1/3}r

where n= 10000

After calculeting we get r=36\rho R^2T


Option 1)

8\rho R^{2}T

Option is incorrect

Option 2)

16 \rho R^{2}T

Option is incorrect

Option 3)

24 \rho R^{2}T

Option is incorrect

Option 4)

36 \rho R^{2}T

Option is correct

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