What will be the value of E and V at the centroid of equilateral if we place charges 2q, –q and -q at the vertices of the equilateral triangle?

  • Option 1)

    E is not equal to 0 and V is equal to zero

  • Option 2)

    V is not equal to 0 and E is equal to zero

  • Option 3)

    Both are equal to zero

  • Option 4)

    None of above

 

Answers (1)

As we learnt in 

Superposition of Electric field -

The resultant electric field at any point is equal to the vector sum of all the electric fields.

 

- wherein

\vec{E}=\vec{E_{1}}+\vec{E_{2}}+\vec{E_{3}}+\cdots\vec{E_{n}}

 

 and

Potential of a System of Charge -

V=\frac{kq_{1}}{r_{1}}+k\frac{q_{2}}{r_{2}}+\frac{k\left ( -q_{3} \right )}{r_{3}}+\cdots

- wherein

 

 Electric field of all the charges do not cancel each other as shown in the figure.

Potential of positive charge is neutralised by other negative charge.

Hence  net potential = 0


Option 1)

E is not equal to 0 and V is equal to zero

This option is correct

Option 2)

V is not equal to 0 and E is equal to zero

This option is incorrect

Option 3)

Both are equal to zero

This option is incorrect

Option 4)

None of above

This option is incorrect

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