Which one of the following reactions of xenon compounds is not feasible ?

  • Option 1)

    XeO_{3}+6HF\rightarrow XeF_{6}+3H_{2}O

  • Option 2)

    3XeF_{4}+6H_{2}O\rightarrow 2Xe+XeO_{3}+12HF+1.5O_{2}

  • Option 3)

    2XeF_{2}+2H_{2}O\rightarrow 2Xe+4HF+O_{2}

  • Option 4)

    XeF_{6}+RbF\rightarrow Rb\left [ XeF_{7} \right ]

 

Answers (1)

As we learnt in

Oxide of Xenon -

XeF_2 + H_2O \rightarrow X_{e}+2HF+\frac{1}{2}O_{2}

2XeF_4 + 4H_2O \rightarrow X_{e}O_{3}+8HF+\frac{1}{2}O_{2}

 

- wherein

Due to high electronegativity of oxygen it form coumpound with Xe

 

 2XeF_{4}+4H_{2}O\rightarrow XeO_{3}+8HF+\frac{1}{2}O_{2}

Reverse reaction is not possible under normal circumstances. 


Option 1)

XeO_{3}+6HF\rightarrow XeF_{6}+3H_{2}O

This option is correct.

Option 2)

3XeF_{4}+6H_{2}O\rightarrow 2Xe+XeO_{3}+12HF+1.5O_{2}

This option is incorrect.

Option 3)

2XeF_{2}+2H_{2}O\rightarrow 2Xe+4HF+O_{2}

This option is incorrect.

Option 4)

XeF_{6}+RbF\rightarrow Rb\left [ XeF_{7} \right ]

This option is incorrect.

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