# Which one of the following reactions of xenon compounds is not feasible ? Option 1) $XeO_{3}+6HF\rightarrow XeF_{6}+3H_{2}O$ Option 2) $3XeF_{4}+6H_{2}O\rightarrow 2Xe+XeO_{3}+12HF+1.5O_{2}$ Option 3) $2XeF_{2}+2H_{2}O\rightarrow 2Xe+4HF+O_{2}$ Option 4) $XeF_{6}+RbF\rightarrow Rb\left [ XeF_{7} \right ]$

P Plabita

As we learnt in

Oxide of Xenon -

$XeF_2 + H_2O \rightarrow X_{e}+2HF+\frac{1}{2}O_{2}$

$2XeF_4 + 4H_2O \rightarrow X_{e}O_{3}+8HF+\frac{1}{2}O_{2}$

- wherein

Due to high electronegativity of oxygen it form coumpound with Xe

$2XeF_{4}+4H_{2}O\rightarrow XeO_{3}+8HF+\frac{1}{2}O_{2}$

Reverse reaction is not possible under normal circumstances.

Option 1)

$XeO_{3}+6HF\rightarrow XeF_{6}+3H_{2}O$

This option is correct.

Option 2)

$3XeF_{4}+6H_{2}O\rightarrow 2Xe+XeO_{3}+12HF+1.5O_{2}$

This option is incorrect.

Option 3)

$2XeF_{2}+2H_{2}O\rightarrow 2Xe+4HF+O_{2}$

This option is incorrect.

Option 4)

$XeF_{6}+RbF\rightarrow Rb\left [ XeF_{7} \right ]$

This option is incorrect.

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