An annular ring with inner and outer radii  R1 and R2 is rolling without slipping with a uniform angular speed. The ratio of the forces experienced by the two particles situated on the inner and outer parts of the ring ,F1/Fis ,

  • Option 1)

    1

  • Option 2)

    \frac{R_{1}}{R_{2}}

  • Option 3)

    \frac{R_{2}}{R_{1}}

  • Option 4)

    \left ( \frac{R_{1}}{R_{2}} \right )^{2}

 

Answers (1)

As we learnt in

Centripetal Force -

F=4m\pi^{2}n^{2}r

F=\frac {4m\pi^{2}n^{2}r} {T^{2}}

F = Centripetal force

\omega= Angular velocity

n = frequency

- wherein

Force acts on the body along the radius and towards centre.

 

 

 

Centripetal force on particle = mR\omega ^{2}

\therefore \: \: \: \frac{F_{1}}{F_{2}}= \frac{mR_{1}\omega ^{2}}{mR_{2}\omega ^{2}}= \frac{R_{1}}{R_{2}}

Correct option is 2.


Option 1)

1

This is an incorrect option.

Option 2)

\frac{R_{1}}{R_{2}}

This is the correct option.

Option 3)

\frac{R_{2}}{R_{1}}

This is an incorrect option.

Option 4)

\left ( \frac{R_{1}}{R_{2}} \right )^{2}

This is an incorrect option.

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