Q

# Help me please, - Electronic devices - JEE Main

The transfer characterstic curve of a transistor, having input and output resistance $100\Omega$ and $100K\Omega$ respectively, is shown in the figure. The Voltage and Power gain are respectively:

• Option 1)

$5\times10^{4},2.5\times10^{6}$

• Option 2)

$5\times 10^{4},5\times10^{5}$

• Option 3)

$5\times10^{4},5\times10^{6}$

• Option 4)

$2.5\times10^{4},2.5\times10^{6}$

Views

$V gain$   $=\left ( \frac{\triangle I_{C}}{\triangle I_{B}} \right )\frac{R_{out}}{R_{in}}$

$=\left ( \frac{5\times 10^{-3}}{100\times10^{-6}} \right )\times10^{3}$

$=\frac{1}{20}\times10^{6}=5\times10^{4}$

$P gain$ = $\left ( \frac{\triangle I_{c}}{\triangle I_{b}} \right )\cdot V gain$

$=\left ( \frac{5\times10^{-3}}{100\times 10^{-6}} \right )\cdot 5\times10^{4}$

$\Rightarrow 2.5\times10^{6}$

$\Rightarrow V gain =5\times10^{4}, P gain=2.5\times10^{6}$

Option 1)

$5\times10^{4},2.5\times10^{6}$

Option 2)

$5\times 10^{4},5\times10^{5}$

Option 3)

$5\times10^{4},5\times10^{6}$

Option 4)

$2.5\times10^{4},2.5\times10^{6}$

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