Given that the equilibrium constant for the reaction

2SO2(g)+O2(g) \rightleftharpoons 2 SO3(g)

has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature?

SO3(g) \rightleftharpoons SO2(g)+1/2 O2(g)

  • Option 1)

    3.6 x 10-3

  • Option 2)

    6.0 x 10-2

  • Option 3)

    1.3 x 10-5

  • Option 4)

    1.8 x 10-3

 

Answers (1)
V Vakul

As we learnt in

Equilibrium constant for the reverse reaction -

Equilibrium constant for the reverse reaction is the inverse of the equilibrium constant for the reaction in the forward direction.

- wherein

K'_{c}=\frac{1}{K_{c}}

{K'_{c}}   is  equilibrium constant for reverse direction.

 

 

 

 SO_{2}(g)+O_{2}(g)\rightleftharpoons 2SO_{3}(g),\ \, \, \, \, \, \, K=278

\therefore    for  SO_{3}(g)\rightleftharpoons SO_{2}(g)+\frac{1}{2}O_{2}(g),\ \: \: \: \: \: K'=\left ( \frac{1}{K} \right )^{1/2}

K'=\left ( \frac{1}{278} \right )^{1/2}=6 \times 10^{-2}


Option 1)

3.6 x 10-3

Incorrect

Option 2)

6.0 x 10-2

Correct

Option 3)

1.3 x 10-5

Incorrect

Option 4)

1.8 x 10-3

Incorrect

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 6999/- ₹ 5/-
Buy Now
Knockout BITSAT 2020

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions