Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me please, If a source of power 4 kW produces 1020 photons/second, the radiation belongs to a part of the spectrum called

If a source of power 4 kW produces 1020 photons/second, the radiation belongs to a part of the spectrum called

Option 1)

\gamma -rays\;

 Option 2)

\; X-rays
Option 3)

ultraviolet rays

 Option 4)

microwaves

Answers (1)

best_answer

As we learnt in

Energy of a photon -

\fn_jvn E= h\nu = \frac{hc}{\lambda }

- wherein

h= Plank's\: constant

\boldsymbol{\nu= frequency\: of \: radiation }

\lambda \rightarrow wave \: length

 

 If wavelength of photon is {\lambda} & n is the number of photon emitted per second then

P=n\frac{hc}{\lambda}

4\times10^{3}=\frac{10^{20}\times 6.62\times{10^{-34}\times{3}\times{10^{8}}}}{\lambda}

{\lambda}=\frac{19.8\times{10^{-26}\times{10^{20}}}}{4\times{10^{3}}}=4.96\times{10^{-9}}

{\lambda}=49.6\AA

This wavelength represent X-rays hence correct answer is 2


Option 1)

\gamma -rays\;

This is an incorrect option.

Option 2)

\; X-rays

This is the correct option.

Option 3)

ultraviolet rays

This is an incorrect option.

Option 4)

microwaves

This is an incorrect option.

Posted by

perimeter

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JAC Chandigarh Counselling 2025: Round 1 seat allotment result out for BTech admissions
anam-khan

JoSAA round 5 seat allotment result 2025 out on josaa.nic.in
anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today

Latest Question