Q

# Help me please, - Laws of motion - JEE Main-2

A spring whose unstretched length is l has a force constant k. The spring is cut into two pieces of unstretched lengths $l_{1}$ and $l_{2}$ where, $l_{1}=nl_{2}$ and n is an integer. The ratio $k_{1}/k_{2}$ of the corresponding force constants, $k_{1}$ and $k_{2}$ will be:

• Option 1)

n

• Option 2)

$\frac{1}{n^{2}}$

• Option 3)

$\frac{1}{n}$

• Option 4)

$n^{2}$

Views

$k_{1}l_{1}=k_{2}l_{2}=kl$

$\frac{k_{1}}{k_{2}}=\frac{l_{2}}{l_{1}}=\frac{l_{2}}{nl_{2}}=\frac{1}{n}$

$l_{1}=nl_{2}$ }

Option 1)

n

Option 2)

$\frac{1}{n^{2}}$

Option 3)

$\frac{1}{n}$

Option 4)

$n^{2}$

Exams
Articles
Questions