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The length of sonometer wire AB is 110 cm where should the two bridges be placed from A to divide the wire in 3 segments whose fundamental frequency are in ratio 1:2:3

  • Option 1)

    (30, 90) cm

  • Option 2)

    (40, 80) cm

  • Option 3)

    (60, 90) cm

  • Option 4)

    (30, 60) cm

 

Answers (1)

best_answer

f\propto \frac{1}{l} \Rightarrow f_{1}:f_{2}:f_{3} = 1:2:3

l_{1}:l_{2}:l_{3}= \frac{1}{1}:\frac{1}{2}:\frac{1}{3}

l_{1}:l_{2}:l_{3}= 6:3:2

l_{1}= \frac{6}{11}\times 110= 60 ,

l_{2}= \frac{3}{11}\times 110= 30,

l_{3}= \frac{2}{11}\times 110= 20 

Sonometer -

It is a device  used to measure velocity of transverse mechanical wave in a stretched wire.

- wherein

The principle of sonometer is based on resonance of string vibration.

 

 


Option 1)

(30, 90) cm

This is incorrect

Option 2)

(40, 80) cm

This is incorrect

Option 3)

(60, 90) cm

This is correct

Option 4)

(30, 60) cm

This is incorrect

Posted by

Avinash

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