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If the distance between planes 4x-2y-4z+1=0  and  4x-2y-4z+d=0 is 7,then d is :

  • Option 1)

    41 or - 42

  • Option 2)

    42 or - 43    

  • Option 3)

    -41 or 43

  • Option 4)

    -42 or 44

 

Answers (1)

best_answer

As we learnt in

Distance between parallel planes (vector form ) -

Distance between \vec{r}\cdot \vec{n}= d  and \vec{r}\cdot \vec{n}= d_{1} is given by 

\frac{\left | d_{1} -d\right |}{\vec{n}}

-

 

 distance = \frac{\begin{vmatrix} d -1 \\ \end{vmatrix}}{\sqrt{4^{2}+2^{2}+4^{2}}} = 7

\begin{vmatrix} d-1 \end{vmatrix}=7\times 6

d-1= \pm 42

d=43 or d=-41

 


Option 1)

41 or - 42

This option is incorrect

Option 2)

42 or - 43    

This option is incorrect

Option 3)

-41 or 43

This option is correct

Option 4)

-42 or 44

This option is incorrect

Posted by

divya.saini

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