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  • Help me please, Time (T), velocity (C) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be :

Time (T), velocity (C) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be :

  • Option 1)

    [ M ]=[ T−1 C−2 h ]

  • Option 2)

    [ M ]=[ T−1 C2 h ]

  • Option 3)

    [ M ]=[ T−1 C−2 h−1 ]

  • Option 4)

    [ M ]=[ T C−2 h ]

     

 

Answers (1)

best_answer

Dimension of length  \left [ L \right ]= \left [ CT \right ]
Dimension\: of \: mass= \frac{\left [ Angular\: Momentum \right ]}{\left [ Velocity \right ]\left [ Length \right ]}

= \frac{\left [ h \right ]}{\left [ C \right ]\left [ CT \right ]}= \left [ C^{-2}T^{-1}h \right ]

Correct Answer is 1

And other options are incorrect

Based on Concept:

Plank's Constant (h) -

M^{1}L^{2}T^{-1}

- wherein

Joule-sec

 

 

 

 

 


Option 1)

[ M ]=[ T−1 C−2 h ]

This is the correct option.

Option 2)

[ M ]=[ T−1 C2 h ]

This is an correct option.

Option 3)

[ M ]=[ T−1 C−2 h−1 ]

This is an incorrect option.

Option 4)

[ M ]=[ T C−2 h ]

 

This is an incorrect option.

Posted by

perimeter

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