Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me solve this A pendulum is made to hang from the ceiling of an elevator. It has period of Ts(for small angles). The elevator is made to accelerate upwards with 10m/s2. The period of the pendulum now will be (assume g = 10m/s2)

A pendulum is made to hang from the ceiling of an elevator. It has period of Ts (for small angles). The elevator is made to accelerate upwards with 10m/s2 . The period of the pendulum now will be (assume g = 10m/s2 )

  • Option 1)

    T \sqrt{2}

  • Option 2)

    Infinte

  • Option 3)

    \frac{T}{\sqrt{2}}

  • Option 4)

    zero

 

Answers (1)

best_answer

\\*T' = 2\pi\sqrt{\frac{l}{g_{net}}} \\*g_{net} = g + a = 10 + 10 = 20 \;m/s^{2} \\* T' = \frac{T}{\sqrt{2}}

 

Time period of simple pendulum accelerating up -

T= 2\pi \sqrt{\frac{l}{g+a}}

- wherein

l= length of pendulum

g= acceleration due to gravity.

a= acceleration of pendulum.

 

 

 


Option 1)

T \sqrt{2}

This is incorrect.

Option 2)

Infinte

This is incorrect.

Option 3)

\frac{T}{\sqrt{2}}

This is correct.

Option 4)

zero

This is incorrect.

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 paper 2 final answer key out; NTA drops 4 questions, 2 from BPlanning
anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in
anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in

Latest Question