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- Help me solve this A thin circular-conducting ring having N turns of radius R is falling with its plane vertical in a horizontal magnetic field B. At the position MNQ, the speed of ring is v, the induced e.m.f. developed across the ring is
- #Birla Institute of Technology & Science Admission Test
- #Engineering
- #Physics
- #Electromagnetic Induction
A thin circular-conducting ring having N turns of radius R is falling with its plane vertical in a horizontal magnetic field B. At the position MNQ, the speed of ring is v, the induced e.m.f. developed across the ring is
- Option 1)
Zero
- Option 2)
and M is at higher potential
- Option 3)
and Q is at higher potential
- Option 4)
and Q is at lower potential
Answers (1)
As we discussed in concept
Motional EMF -
- wherein
magnetic field
length
velocity of u perpendicular to uniform magnetic field.
Emf induced = (B.(MQ) v) N
= B . (2R) v N,
Q will be at lower potential.
Option 1)
Zero
This option is incorrect.
Option 2)
and M is at higher potential
This option is incorrect.
Option 3)
and Q is at higher potential
This option is incorrect.
Option 4)
and Q is at lower potential
This option is correct.
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