According to Bohr’s theory, the angular momentum of an electron in 5th orbit is

  • Option 1)

    25\frac{h}{\pi }

  • Option 2)

    1.0\frac{h}{\pi }

  • Option 3)

    10\frac{h}{\pi }

  • Option 4)

    2.5\frac{h}{\pi }

 

Answers (2)

As we learnt in 

Bohr radius of nth orbit -

r_{n}= 0.529 \frac{n^{2}}{z}A^{0}

where Z is atomic number

-

 

 Angular momentum of the electron, m\nu r= \frac{nh}{2\pi } when \: \: n= 5(given)

\therefore \: \: \: \: angular \: \: momentum\: \: = \frac{5h}{2\pi }= 2.5\frac{h}{\pi }

 


Option 1)

25\frac{h}{\pi }

Incorrect Option

Option 2)

1.0\frac{h}{\pi }

Incorrect Option

Option 3)

10\frac{h}{\pi }

Incorrect Option

Option 4)

2.5\frac{h}{\pi }

Correct Option

N neha

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