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  • Help me solve this According to Bohr’s theory, the angular momentum of an electron in 5th orbit is

According to Bohr’s theory, the angular momentum of an electron in 5th orbit is

  • Option 1)

    25\frac{h}{\pi }

  • Option 2)

    1.0\frac{h}{\pi }

  • Option 3)

    10\frac{h}{\pi }

  • Option 4)

    2.5\frac{h}{\pi }

 

Answers (2)

best_answer

As we learnt in 

Bohr radius of nth orbit -

r_{n}= 0.529 \frac{n^{2}}{z}A^{0}

where Z is atomic number

-

 

 Angular momentum of the electron, m\nu r= \frac{nh}{2\pi } when \: \: n= 5(given)

\therefore \: \: \: \: angular \: \: momentum\: \: = \frac{5h}{2\pi }= 2.5\frac{h}{\pi }

 


Option 1)

25\frac{h}{\pi }

Incorrect Option

Option 2)

1.0\frac{h}{\pi }

Incorrect Option

Option 3)

10\frac{h}{\pi }

Incorrect Option

Option 4)

2.5\frac{h}{\pi }

Correct Option

Posted by

Aadil

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