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At what speed should a source of sound move so that the observer finds the apparent frequency equal to half of the original frequency.

  • Option 1)

    \frac{v}{2}

  • Option 2)

    2v

  • Option 3)

    \frac{v}{4}

  • Option 4)

    v

 

Answers (1)

best_answer

v' = \frac{c}{c+v_{s}}v_{o} \Rightarrow \frac{v_{o}}{2} = \frac{c}{c+v_{s}}v_{o} \Rightarrow v_{s} = v

 

Frequency when observer is stationary and source is moving away from observer -

\nu {}'= \nu _{0}.\frac{C}{C+V_{s}}
 

- wherein

C= speed of sound

V_{s}= speed of source

\nu _{0}= original frequency

\nu {}'= apparent frequency

 

 

 


Option 1)

\frac{v}{2}

This is incorrect.

Option 2)

2v

This is incorrect.

Option 3)

\frac{v}{4}

This is incorrect.

Option 4)

v

This is correct.

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Aadil

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