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Help me solve this - Atomic Structure - BITSAT-3

The number of quanta of radiations of V=4.67\times10^{13} HZ that must be absorbed in order to melt 5g of ice is (the energy required to melt 1g of ice is 333 J)

  • Option 1)

    5.38\times10^{22}

  • Option 2)

    30.9\times10^{21}

  • Option 3)

    4.67\times10^{13}

  • Option 4)

    6.62\times10^{34}

 
Answers (1)
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V Vakul

As we learnt in 

The energy (E) of a quantum of radiation -

E=hv

Where h is plank’s constant and \nu is frequency

-

 

 Energy required=5\times 333\, \, J

n\times h\times v=5\times 333J\\*\\*n=\frac{5\times 333}{4.67\times 10^{13}\times 6.62\times 10^{-34}}=5.38\times 10^{22}

 


Option 1)

5.38\times10^{22}

Correct

Option 2)

30.9\times10^{21}

Incorrect

Option 3)

4.67\times10^{13}

Incorrect

Option 4)

6.62\times10^{34}

Incorrect

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