The atomic numbers of vanadium $(V),$ chromium  $(Cr),$ manganese $(Mn)$ and iron $(Fe)$ are respectively 23, 24, 25 and 26. Which one of these may be expected to have the highest second ionisation enthalpy? Option 1) $V$ Option 2) $Cr$ Option 3) $Mn$ Option 4) $Fe$

P Plabita

As we learnt in

Ionization Enthalpies -

Due to increase in nuclear charge, there is in an increase in ionization Enthalpies from left to right with small variation.

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Order of second ionisation enthalpy is Cr>Fe>Mn>V

Option 1)

$V$

This option is incorrect.

Option 2)

$Cr$

This option is correct.

Option 3)

$Mn$

This option is incorrect.

Option 4)

$Fe$

This option is incorrect.

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