How many unit cells are present in a cube-shaped deal crystal of NaCl of mass 1.00 g
[ Atomic masses : Na =23,Cl=35.5]
As we learnt in
Density of cubic unit cell -
- wherein
Where,
d = density of crystal
z = no. of effective constituent particles in one unit cell
M = molecular weight
a = edge length of unit cell
No = 6.022*1023
( In NaCl each unit cell has 4 NaCl units. Hence z = 4)
Correct option is 1.
Option 1)
This is the correct option.
Option 2)
This is an incorrect option.
Option 3)
This is an incorrect option.
Option 4)
This is an incorrect option.
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