In which of the following ionization processes, the bond order has increased and the magnetic behaviour has changed?

  • Option 1)

    N_{2}\rightarrow N{_{2}}^{+}

  • Option 2)

    C_{2}\rightarrow C{_{2}}^{+}

  • Option 3)

    NO\rightarrow NO^{+}

  • Option 4)

    O_{2}\rightarrow O{_{2}}^{+}

 

Answers (2)

As we learnt in 

Bond Order -

Bond order is defined as one half the difference between the number of electrons present in the bonding and the antibonding orbitals.

- wherein

Bond \:Order=\frac{N_{b}-{N_{a}}}{2}

 

 and

Magnetic behaviour of molecule -

If  all the molecular orbitals in a molecule are doubly occupied, the substance is diamagnetic

- wherein

However if one or more molecular orbital are singly occupied it is paramagnetic e.g. O2

 

 

Molecular orbital configuration of

\Rightarrow paramagnetic

Bond\: order\: = \frac{10-6}{2}= 2

Bond\: order\: = \frac{10-5}{2}= 2.5

 

Bond\: order\: = \frac{10-4}{2}=3

Bond\: order\: = \frac{9-4}{2}= 2.5

Bond\: order\: = \frac{8-4}{2}= 2

Bond\: order\: = \frac{7-4}{2}= 1.5

Bond\: order\: = \frac{10-5}{2}= 2.5

Bond\: order\: = \frac{10-4}{2}=3


Option 1)

N_{2}\rightarrow N{_{2}}^{+}

This option is incorrect

Option 2)

C_{2}\rightarrow C{_{2}}^{+}

This option is incorrect

Option 3)

NO\rightarrow NO^{+}

This option is correct

Option 4)

O_{2}\rightarrow O{_{2}}^{+}

This option is incorrect

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