Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me solve this - Oscillations and Waves - JEE Main-7

The ratio of densities of nitrogen and oxygen is 14:16. The temperature at which the speed of sound in nitrogen will be same at that in oxygen at 55\degree C is

  • Option 1)

    35\degree C

  • Option 2)

    48\degree C

  • Option 3)

    65\degree C

  • Option 4)

    14\degree C

 

Answers (1)

best_answer

v = \sqrt{\frac{\gamma RT}{M}} \Rightarrow \frac{T_{N}}{T_{O}} = \frac{M_{N}}{M_{O}}

\Rightarrow \frac{T_{N}}{273 + 55} = \frac{14}{16} = \frac{7}{8}

\Rightarrow T_{N} = 287 K = 14 ^{o} C

 

Effect of temperature on speed of sound -

\because \frac{P}{\rho }= \frac{RT}{M}

\therefore V= \sqrt{\frac{\gamma RT}{M}}

 

- wherein

V \alpha \sqrt{T}

T is in Kelvin

So velocity increses with increase in temperature.

 

 

 

 


Option 1)

35\degree C

This is incorrect.

Option 2)

48\degree C

This is incorrect.

Option 3)

65\degree C

This is incorrect.

Option 4)

14\degree C

This is correct.

Posted by

prateek

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question