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  • Help me solve this The decreasing order of electrical conductivity of the following aqueous solution is:0.1 M Formic acid (A),0.1 M Acetic acid (B),0.1 M Benzoic acid (C)

The decreasing order of electrical conductivity of the following aqueous solution is:

0.1 M Formic acid (A),

0.1 M Acetic acid (B),

0.1 M Benzoic acid (C)

  • Option 1)

    A > C > B

  • Option 2)

    C > B > A

  • Option 3)

    A > B > C

  • Option 4)

    C > A > B

Answers (1)

best_answer

A > C > B

K \rightarrow depends on No. of ions perfect in a unit volume of solution 

No. of ions depends on the degree of dissociation (\alpha)

\alpha =\sqrt{\frac{kq}{C}}

Ka of formic acid =  10^{-4}

Ka of Benzoic acid = 6\times 10^{-5}

order of Ka      HCOOH > C_{6}H_{5}COOH > CH_{3}COOH

                            (A)                            (C)                            (B)

order of \alpha     HCOOH > C_{6}H_{5}COOH > CH_{3}COOH

                            (A)                            (C)                            (B)

order of K    HCOOH > C_{6}H_{5}COOH > CH_{3}COOH

                           (A)                             (C)                             (B)                 

 

 

 


Option 1)

A > C > B

Option 2)

C > B > A

Option 3)

A > B > C

Option 4)

C > A > B

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