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# Help me solve this The eye can be regarded as a single refracting surface. The radius of curvature of this surface is equal to that of cornea (7.8mm) . This surface separates two media of refractive indices 1 and 1.34. Calculate the distance from the refr

The eye can be regarded as a single refracting surface. The radius of curvature of this surface is equal to that of cornea (7.8mm) . This surface separates two media of refractive indices 1 and 1.34. Calculate the distance from the refracting surface at which a parallel beam of light will come to focus.

• Option 1)

$4.0 \: cm$

• Option 2)

$2 \: cm$

• Option 3)

$3.1 \: cm$

• Option 4)

$1.0 \: cm$

Views

Refraction through spherical surface -

$\frac{\mu _{2}}{v}-\frac{\mu _{1}}{u}= \frac{\mu _{2}-\mu _{1}}{R}$

- wherein

$u=$ Object distance

$v=$ image distance

$R=$ Radius of curvature

$\left ( \frac{1.34}{V} - \frac{1}{\infty } \right ) = \frac{1.34 - 1}{7.8}$

$V = 30.7mm\approx 3.1cm$

Option 1)

$4.0 \: cm$

Option 2)

$2 \: cm$

Option 3)

$3.1 \: cm$

Option 4)

$1.0 \: cm$

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