A plane which bisects the angle between the two given planes 2x-y+2z-4=0 and x-2y+2z-2=0, passes through the points:

 

  • Option 1)

    (1,-4,1)

  • Option 2)

    (1,4,-1)

  • Option 3)

    (2,4,1)

     

  • Option 4)

    (2,-4,1)

Answers (1)

|\frac{x+2y+2z-2}{3}|=|\frac{2x-y+2z-4}{3}|

=> Required equation of planes are 

x-3y-2=0

and

3x+y+4z-6=0

Now, substituting the options we will get , the point ( 2, -4 , 1 ).


Option 1)

(1,-4,1)

Option 2)

(1,4,-1)

Option 3)

(2,4,1)

 

Option 4)

(2,-4,1)

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