# A plane which bisects the angle between the two given planes $2x-y+2z-4=0$ and $x-2y+2z-2=0$, passes through the points:Option 1)(1,-4,1)Option 2)(1,4,-1)Option 3)(2,4,1)  Option 4)(2,-4,1)

$|\frac{x+2y+2z-2}{3}|=|\frac{2x-y+2z-4}{3}|$

=> Required equation of planes are

$x-3y-2=0$

and

$3x+y+4z-6=0$

Now, substituting the options we will get , the point ( 2, -4 , 1 ).

Option 1)

(1,-4,1)

Option 2)

(1,4,-1)

Option 3)

(2,4,1)

Option 4)

(2,-4,1)

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