A cell is connected between the points A and C of a circular conductor ABCD of centre O with angle AOC=60o If B1 and B2 are the magnitudes of the magnetic fields at O due to the currents in ABC and ADC respectively, the ratio B1/B2

  • Option 1)

    0.2

  • Option 2)

    6

  • Option 3)

    1

  • Option 4)

    5

 

Answers (1)

As we learnt in 

Arc subtends angle theta at the centre -

B=\frac{\mu_{0}}{4\pi }.\frac{\theta i}{r}

- wherein

 

 \frac{R_{ADC}}{R_{ABC}}=\frac{1}{5}     \Rightarrow \frac{I_{ABC}}{I_{ADC}}=\frac{1}{5} 

\frac{B_1}{B_2}=(\frac{I_{ABC}}{I_{ADC}})(\frac{300^{0}}{60^{0}})

=1.[B=\frac{\mu _oi}{4\pi r}\theta ]


Option 1)

0.2

incorrect

Option 2)

6

incorrect

Option 3)

1

correct

Option 4)

5

incorrect

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