A light string passing over a smooth light pulley  connects two blocks of masses m1 and m2  ( vertically) .  If the acceleration of the system is g/8,  then the ratio of the masses is

  • Option 1)

    8 : 1

  • Option 2)

    9 : 7

  • Option 3)

    4 : 3

  • Option 4)

    5 : 3

 

Answers (1)

As we learnt in

Motion of connected blocks over pulley -

Equation of motion for   m_{1}

F_{net}=T-m_{1}g=m_{1}a

Equation of Motion for   m_{2}

F_{net}=m_{2}g-T=m_{2}a

 

- wherein

a=\frac{[m_{2}-m_{1}\:]g}{m_{1}+m_{2}}

T=\frac{2m_{1}m_{2}\:g}{m_{1}+m_{2}}


 

 

 

 

\frac{a}{g}=\frac{(m_{1}-m_{2})}{(m_{1}+m_{2})}

 \therefore\; \; \frac{1}{8}=\frac{(m_{1}-m_{2})}{(m_{1}+m_{2})}   

or  \frac{m_{1}}{m_{2}}=\frac{9}{7}

Correct option is 2.


Option 1)

8 : 1

This is an incorrect option.

Option 2)

9 : 7

This is the correct option.

Option 3)

4 : 3

This is an incorrect option.

Option 4)

5 : 3

This is an incorrect option.

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