Get Answers to all your Questions

header-bg qa

A spring has a certain mass supended from it and its period for vertiacal oscillation is T. The spring is now cut into equal halves and the same mass is suspended from one of the halves. The period of the vertial oscillation is now

  • Option 1)

    \frac{T}{}2

  • Option 2)

    \frac{T}{\sqrt{2}}

  • Option 3)

    \sqrt{2} T

  • Option 4)

    2T

 

Answers (1)

best_answer

T = 2\pi\sqrt{\frac{m}{k}}. Also Spring\; constant\; (k)\; \alpha\; \frac{1}{Length\;(l)}

When the spring is hal in length, then k becomes twice.

\therefore T' = 2\pi \sqrt{\frac{m}{2k}} \Rightarrow \frac{T'}{T} = \frac{1}{\sqrt{2}} \Rightarrow T' = \frac{T}{\sqrt{2}}

 

Time period of oscillation for spring mass system -

T= 2\pi \sqrt{\frac{m}{K}}

- wherein

m = mass of block

K = spring constant

 

 

 


Option 1)

\frac{T}{}2

This is incorrect.

Option 2)

\frac{T}{\sqrt{2}}

This is correct.

Option 3)

\sqrt{2} T

This is incorrect.

Option 4)

2T

This is incorrect.

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE