An element has a face-centred cubic (fcc) structure with a cell edge of a. The distance between the centres of two nearest tetrahedral voids in the lattice is :
No. of atoms(z) for face centered unit cell -
Lattice points: at corners and face centers of unit cell.
For face centered cubic (FCC), z=4.
Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell -
We know that, in fcc cell unit, the tetrahedral voids are located at body diagonal at a distance from the corners.
Now, (Tv= tetrahedral voids)
Now, & are similar triangle,
distance between two nearest tetrahedral voids is
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