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Bond order of 1.5 is shown by:

  • Option 1)

    \text{O}_{2}^{+}

  • Option 2)

    \text{O}_{2}^{-}

  • Option 3)

    \text{O}_{2}^{2-}

  • Option 4)

    \text{O}_{2}

 

Answers (1)

best_answer

As learnt (Concept Missing)

Bonder \: order=\frac{Nb-Na}{2}

For \: O_{2}^{+} \: : \: Bond \: order \: = \frac{10-5}{2}=2.5

For \: O_{2}^{-} \: : \: Bond \: order \: = \frac{10-7}{2}=1.5

For \: O_{2}^{2-} \: : \: Bond \: order \: = \frac{10-8}{2}=1.0

For \: O_{2} \: : \: Bond \: order \: = \frac{10-6}{2}=2


Option 1)

\text{O}_{2}^{+}

This option is incorrect

Option 2)

\text{O}_{2}^{-}

This option is correct

Option 3)

\text{O}_{2}^{2-}

This option is incorrect

Option 4)

\text{O}_{2}

This option is incorrect

Posted by

Plabita

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