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Charge -q and +Q located at A and B, respectively, constitute an electric dipole.Distance AB=2a, O is the mid point of the dipole and OP is perpendicular to AB. A charge Q is places at P where OP=y and y>>2a. The charge Q experience an electrostatic force F. If Q is now moved along the equational line to P' such that OP{}'= \left ( \frac{y}{3} \right ), the force on Q woll be close to : \left ( \frac{y}{3} >>2a\right ),

 

  • Option 1)

    9F

  • Option 2)

    27 F

  • Option 3)

    F/3

  • Option 4)

    3F

Answers (1)

best_answer

 

At equatorial Point -

E_{equi}= \frac{kP}{\left ( r^{2}+l^{2} \right )^{\frac{3}{2}}}

If r >> l

E_{equi}= \frac{1}{4\pi \varepsilon _{0}}\frac{P}{r^{3}}

V_{equi}= 0

 

- wherein

Angle between Eaxial and P is 180°.

 

Electric field of equitorial plane of dipole =\frac{-K\overrightarrow{P}}{r^{3}}

At P, F = \frac{-K\overrightarrow{P}Q}{r^{3}}

At P' , F^{'} = \frac{-K\overrightarrow{P}Q}{\frac{r}{3}^{3}} = 27F


Option 1)

9F

Option 2)

27 F

Option 3)

F/3

Option 4)

3F

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