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The given plots represent the variation of the concrntration of a reactant $R$ with time for two different reactions (i) and (ii). The respective orders of the reactions are :

Option 1)
$1,0$
Option 2)
$1,1$
Option 3)
$0,1$
Option 4)
$0,2$

Answers (1)

S solutionqc

$\left ( R \right )$ =Concentration of reactant at $t$ time

1st order : $K=\frac{1}{t}ln\left ( \frac{C_{o}}{C_{t}} \right )\Rightarrow Kt=lnC_{o}-lnC_{t}$

$lnC_{t}=-Kt +lnC_{o}$

Zero order $\frac{C_{t}}{y}=C_{o}-\frac{Kt}{mx}$

$m=-K$ (negative)

So,order are $1,0$ respectively

Option 1)
$1,0$
Option 2)

$1,1$

Option 3)

$0,1$

Option 4)

$0,2$

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