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# Engineering

The given plots represent the variation of the concrntration of a reactant R with time for two different reactions (i) and (ii). The respective orders of the reactions are :

  • Option 1)

     1,0

  • Option 2)

     1,1

  • Option 3)

     0,1

  • Option 4)

    0,2

Answers (1)
S solutionqc

\left ( R \right ) =Concentration of reactant at t time

1st  order : K=\frac{1}{t}ln\left ( \frac{C_{o}}{C_{t}} \right )\Rightarrow Kt=lnC_{o}-lnC_{t}

                                                       lnC_{t}=-Kt +lnC_{o}

Zero order   \frac{C_{t}}{y}=C_{o}-\frac{Kt}{mx}

            m=-K  (negative)

So,order are 1,0 respectively            


Option 1)

 1,0

Option 2)

 1,1

Option 3)

 0,1

Option 4)

0,2

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