The straight line L at a distance of 4 units from the origin makes

positive intercepts on the coordinate axes and the perpendicular

from the origin to this line makes an angle of 60^{\circ} with the line 

x+y=0 . Then an equation of the line L is :

  • Option 1)

    x+\sqrt3y=8

  • Option 2)

    (\sqrt3+1)x+(\sqrt3-1)y=8\sqrt2

  • Option 3)

    \sqrt3x+y=8

  • Option 4)

    (\sqrt3-1)x+(\sqrt3+1)y=8\sqrt2

 

Answers (1)

Hence, the equation of line is 

xcos\theta+ysin\theta=p

xcos75^{\circ}+ysin75^{\circ}=4

x(\frac{\sqrt3-1}{2\sqrt2})+y(\frac{\sqrt3+1}{2\sqrt2})=4

(\sqrt3+1)x+(\sqrt3-1)y=8\sqrt2


Option 1)

x+\sqrt3y=8

Option 2)

(\sqrt3+1)x+(\sqrt3-1)y=8\sqrt2

Option 3)

\sqrt3x+y=8

Option 4)

(\sqrt3-1)x+(\sqrt3+1)y=8\sqrt2

Preparation Products

Knockout JEE Main July 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Rank Booster JEE Main 2020

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 9999/- ₹ 4999/-
Buy Now
Test Series JEE Main July 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 17999/- ₹ 11999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 19999/-
Buy Now
Exams
Articles
Questions