Get Answers to all your Questions

header-bg qa

The Kirchhoff’s first law \left ( \sum i= 0 \right )  and second law \left ( \sum iR= \sum E \right )   where the symbols have their usual meanings, are respectively based on

  • Option 1)

    conservation of charge, conservation of energy

  • Option 2)

    conservation of charge, conservation of momentum

  • Option 3)

    conservation of energy, conservation of charge

  • Option 4)

    conservation of momentum, conservation of charge.

 

Answers (2)

 

As we learnt in

In closed loop -

-i_{1}}R_{1} + i_{2}}R_{2} -E_{1}-i_{3}}R_{3}+E_{2}+E_{3}-i_{4}}R_{4}=0

- wherein

 

 and

Kirchoff's first law -

\sum i=0

i_{1}+i_{3}=i_{2}+i_{4}

- wherein

Kirchhoff's first law   \left [ \sum i= 0 \right ]   is based on conservation of charge

Kirchhoff's second law   \left [ \sum iR= \sum E \right ]   is based on conservation of energy.

 

 


Option 1)

conservation of charge, conservation of energy

This is correct.

Option 2)

conservation of charge, conservation of momentum

This is incorrect.

Option 3)

conservation of energy, conservation of charge

This is incorrect.

Option 4)

conservation of momentum, conservation of charge.

This is incorrect.

Posted by

Vakul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE