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The crystal field stabilization energy (CFSE) of $\left [ Fe\left ( H_{2}O \right )_{6} \right ]Cl_{2}$ and $K_{2}\left [ NiCl_{4} \right ]$ , respectively , are :
Option 1)
$-0.6\Delta _{0} \; and\; -0.8\Delta _{t}$
Option 2)
$-0.4\Delta _{0}\; and\; -0.8\Delta _{t}$
Option 3)
$-2.4\Delta _{0}\; and\; -1.2\Delta _{t}$
Option 4)
$-0.4\Delta _{0}\; and\; -1.2\Delta _{t}$

Answers (1)

best_answer

(a) CFSE of $\left [ Fe\left ( H_{2}O \right )_{6} \right ]Cl_{2}\rightarrow \left [ Fe \left ( H_{2}O \right )_{6} \right ]^{2+}+2Cl^{-}$

$Fe^{2+}\rightarrow \left [ Ar \right ]3d^{6}$

$H_{2}O$ is weak ligands so pairing not take place

$t_{2g}^{2.1.1}$ eg. $1.1$

CFSE= $-0.4\times 4\Delta _{0}+0.6\times 2\Delta _{0}=-0.4\Delta _{0}$

(b) CFSE of $K_{2}\left [ NiCl_{4} \right ]$

$Ni^{2+}\rightarrow \left [ Ar \right ]3d$

$Cl^{-}\rightarrow$ weak field ligand pairing not take place & also have tetrahedra geometry.

e.g. $^{2.2}$ , $t_{2g}^{2.1.1}$

CFSE= $-0.6\times 4\Delta _{t}+0.4\times 4\Delta _{t}=0.8\Delta _{t}$

Option 1)

$-0.6\Delta _{0} \; and\; -0.8\Delta _{t}$

Option 2)
$-0.4\Delta _{0}\; and\; -0.8\Delta _{t}$
Option 3)

$-2.4\Delta _{0}\; and\; -1.2\Delta _{t}$

Option 4)

$-0.4\Delta _{0}\; and\; -1.2\Delta _{t}$

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