Q

# Help me understand! - Electromagnetic Induction and Alternating currents - JEE Main

Two coils 'P' and 'Q' are seperated by some distance . When a current of 3 A flows through coil 'P' , a magnetic flux of $10^{-3}\:Wb$ passes through 'Q' . No current is passed through 'Q'.When no current passes through 'P' and a current of 2A passes through 'Q', the flux through 'P' is :

• Option 1)

$6.67\times10^{-4}Wb$

• Option 2)

$3.67\times10^{-3}Wb$

• Option 3)

$6.67\times10^{-3}Wb$

• Option 4)

$3.67\times10^{-4}Wb$

Views

$\phi=Mi$

$10^{-3}=M(3)------(1)$

$\phi=M(2)------(2)$

$\Rightarrow\frac{10^{-3}}{\phi}=\frac{3}{2}$

$\Rightarrow=\phi\frac{2}{3}\times10^{-3}=6.67\times10^{-4}\:Wb$

Option 1)

$6.67\times10^{-4}Wb$

Option 2)

$3.67\times10^{-3}Wb$

Option 3)

$6.67\times10^{-3}Wb$

Option 4)

$3.67\times10^{-4}Wb$

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