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Number of atoms in the unit cell of Na (BCC) and Mg (FCC) are respectively

  • Option 1)

    4 and 4

  • Option 2)

    2 and 4

  • Option 3)

    4 and 2

  • Option 4)

    1 and 1

 

Answers (1)

best_answer

Number of atom in BCC unit cell = 8\times \frac{1}{8}+1=2

Number of atom in FCC unit cell = 6\times \frac{1}{2}+8\times \frac{1}{8}=4

 

No. of atoms(z) for face centered unit cell -

Lattice points: at corners and face centers of unit cell.

For face centered cubic (FCC), z=4.

- wherein

 

 


Option 1)

4 and 4

This is incorrect

Option 2)

2 and 4

This is correct

Option 3)

4 and 2

This is incorrect

Option 4)

1 and 1

This is incorrect

Posted by

divya.saini

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