Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me understand! - Sets, Relations and Functions - JEE Main

Let R= \left \{ \left ( 3,3 \right ) \left ( 6,6 \right ),\left ( 9,9 \right )\left ( 12,12 \right )\left ( 6,12 \right )\left ( 3,9 \right ),\left ( 3,12 \right )\left ( 3,6 \right )\right \}

be a relation on the set  A=\left \{ 3,6,9,12 \right \} The relation is

  • Option 1)

    reflexive and symmetric only

  • Option 2)

    an equivalence relation

  • Option 3)

    reflexive only

  • Option 4)

    reflexive and transitive only.

 

Answers (1)

As we learnt in

Equivalence Relation -

A relation which is reflexive, symmetric & transitive is called Equivalence Relation.

-

 

 Let R = {(3, 3) (6, 6) (9, 9) (12, 12) (6, 12) (3, 9) (3, 12) (3, 6)}

A = {3, 6, 9, 12}

Now, (6, 12)\epsilon R  but (6, 12) \not \epsilon R so it is not symmetric.

Now (6, 12)\epsilon R

        (12, 12)\epsilon R

So (6, 12)\epsilon R so it is transitive.

Correct option is 4.

 


Option 1)

reflexive and symmetric only

This is an incorrect option.

Option 2)

an equivalence relation

This is an incorrect option.

Option 3)

reflexive only

This is an incorrect option.

Option 4)

reflexive and transitive only.

This is the correct option.

Posted by

Vakul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JoSAA 2024 round 4 seat allotment results out at josaa.nic.in; report online by July 15

Latest Question